# Section 8.2 Part 2: Analysis

While this comment could have been absorbed into the previous comment on this section, it is important to note that Hungerford specifies that  does not imply that  for every  when dealing with groups and normal groups.

I find it interesting that the statement  for every , where $aNa^-1 ={ana^-1\mid n\in Na^-1 Na=Na\in G$\$ are equivalent.